Ratio of present ages of A and B is 7:5. After 12 years, the ratio becomes 8:8. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:5. After 12 years, the ratio becomes 8:8. Present age of A is?

A. 94 years

B. 196 years

C. 98 years

D. 103 years

Answer: Option C

Solution (By JKSSB Mock Tests)

Let ages 7k and 5k. Then (7k + 12)/(5k + 12) = 8/8. Solving gives k ≈ 14, age of A = 7*14 = 98.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

If a:b = 6:5 and b:c = 5:11, then a:b:c = ?

A. 5:5:12

B. 6:5:11

C. 12:10:22

D. 6:6:11

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Correct Answer: Option B

Explanation:
Combine ratios: a:b = 6:5, b:c = 5:11 ⇒ a:b:c = 6:5:11.

This question belongs to: Maths Ratio and Proportion

Question #2

Two numbers are in ratio 9:12. Their difference is 74. What is their sum?

A. 105

B. 210

C. 270

D. 355

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Correct Answer: Option B

Explanation:
Numbers 9k, 12k. Difference |9-12|k = 74 ⇒ k = 24. Sum = (9+12)k ≈ 210.

This question belongs to: Maths Ratio and Proportion

Question #3

Two numbers are in the ratio 4:3 and their sum is 631. Find the numbers.

A. 360 and 270

B. 347 and 287

C. 720 and 540

D. 380 and 258

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Correct Answer: Option A

Explanation:
Numbers = 4k and 3k. 4k + 3k = 631 ⇒ k = 90. Thus, numbers are 360 and 270.

This question belongs to: Maths Ratio and Proportion

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