Ratio of present ages of A and B is 7:7. After 10 years, the ratio becomes 10:8. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:7. After 10 years, the ratio becomes 10:8. Present age of A is?

A. 150 years

B. 308 years

C. 159 years

D. 154 years

Answer: Option D

Solution (By JKSSB Mock Tests)

Let ages 7k and 7k. Then (7k + 10)/(7k + 10) = 10/8. Solving gives k ≈ 22, age of A = 7*22 = 154.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Two numbers are in the ratio 5:6 and their sum is 406. Find the numbers.

A. 360 and 432

B. 180 and 216

C. 160 and 225

D. 196 and 203

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Correct Answer: Option B

Explanation:
Numbers = 5k and 6k. 5k + 6k = 406 ⇒ k = 36. Thus, numbers are 180 and 216.

This question belongs to: Maths Ratio and Proportion

Question #2

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Find the mean proportional between 4 and 21.

A. 18

B. 12

C. 9

D. 25

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Correct Answer: Option C

Explanation:
Mean proportional = √(4 × 21) = √(84) = 9.

This question belongs to: Maths Ratio and Proportion

Question #3

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Two numbers are in the ratio 11:15 and their sum is 202. Find the numbers.

A. 61 and 114

B. 154 and 210

C. 99 and 94

D. 77 and 105

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Correct Answer: Option D

Explanation:
Numbers = 11k and 15k. 11k + 15k = 202 ⇒ k = 7. Thus, numbers are 77 and 105.

This question belongs to: Maths Ratio and Proportion

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