Ratio of present ages of A and B is 7:8. After 11 years, the ratio becomes 10:10. Present age of A is? MCQ with Answer and Explanation

Question

Share Report Error

Ratio of present ages of A and B is 7:8. After 11 years, the ratio becomes 10:10. Present age of A is?

A. 161 years

B. 322 years

C. 166 years

D. 156 years

Answer: Option A

Solution (By JKSSB Mock Tests)

Let ages 7k and 8k. Then (7k + 11)/(8k + 11) = 10/10. Solving gives k ≈ 23, age of A = 7*23 = 161.

This question belongs to: Maths Ratio and Proportion

Request complete Subject PDF

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Ratio and Proportion Questions

Question #1

Find the mean proportional between 20 and 36.

A. 26

B. 52

C. 56

D. 29

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option A

Explanation:
Mean proportional = √(20 × 36) = √(720) = 26.

This question belongs to: Maths Ratio and Proportion

Question #2

If a:b = 4:10 and b:c = 10:10, then a:b:c = ?

A. 3:10:11

B. 4:10:10

C. 8:20:20

D. 4:11:10

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option B

Explanation:
Combine ratios: a:b = 4:10, b:c = 10:10 ⇒ a:b:c = 4:10:10.

This question belongs to: Maths Ratio and Proportion

Question #3

Find the mean proportional between 20 and 62.

A. 38

B. 70

C. 82

D. 35

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option D

Explanation:
Mean proportional = √(20 × 62) = √(1240) = 35.

This question belongs to: Maths Ratio and Proportion

Explore All Ratio and Proportion MCQs