Ratio of present ages of A and B is 7:8. After 4 years, the ratio becomes 10:11. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:8. After 4 years, the ratio becomes 10:11. Present age of A is?

A. 138 years

B. 133 years

C. 266 years

D. 128 years

Answer: Option B

Solution (By JKSSB Mock Tests)

Let ages 7k and 8k. Then (7k + 4)/(8k + 4) = 10/11. Solving gives k ≈ 19, age of A = 7*19 = 133.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Two numbers are in the ratio 5:6 and their sum is 406. Find the numbers.

A. 360 and 432

B. 196 and 203

C. 160 and 225

D. 180 and 216

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Correct Answer: Option D

Explanation:
Numbers = 5k and 6k. 5k + 6k = 406 ⇒ k = 36. Thus, numbers are 180 and 216.

This question belongs to: Maths Ratio and Proportion

Question #2

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If a:b = 2:7 and b:c = 7:8, then a:b:c = ?

A. 1:7:9

B. 2:8:8

C. 2:7:8

D. 4:14:16

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Correct Answer: Option C

Explanation:
Combine ratios: a:b = 2:7, b:c = 7:8 ⇒ a:b:c = 2:7:8.

This question belongs to: Maths Ratio and Proportion

Question #3

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Two numbers are in ratio 12:10. Their difference is 74. What is their sum?

A. 312

B. 132

C. 387

D. 264

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Correct Answer: Option D

Explanation:
Numbers 12k, 10k. Difference |12-10|k = 74 ⇒ k = 37. Sum = (12+10)k ≈ 264.

This question belongs to: Maths Ratio and Proportion

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