Ratio of present ages of A and B is 7:8. After 4 years, the ratio becomes 10:11. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 7:8. After 4 years, the ratio becomes 10:11. Present age of A is?

A. 266 years

B. 133 years

C. 138 years

D. 128 years

Answer: Option B

Solution (By JKSSB Mock Tests)

Let ages 7k and 8k. Then (7k + 4)/(8k + 4) = 10/11. Solving gives k ≈ 19, age of A = 7*19 = 133.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

If a:b = 7:7 and b:c = 7:7, then a:b:c = ?

A. 6:7:8

B. 7:7:7

C. 7:8:7

D. 14:14:14

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Correct Answer: Option B

Explanation:
Combine ratios: a:b = 7:7, b:c = 7:7 ⇒ a:b:c = 7:7:7.

This question belongs to: Maths Ratio and Proportion

Question #2

Two numbers are in the ratio 14:12 and their sum is 772. Find the numbers.

A. 406 and 348

B. 389 and 367

C. 812 and 696

D. 421 and 329

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Correct Answer: Option A

Explanation:
Numbers = 14k and 12k. 14k + 12k = 772 ⇒ k = 29. Thus, numbers are 406 and 348.

This question belongs to: Maths Ratio and Proportion

Question #3

Ratio of present ages of A and B is 3:6. After 11 years, the ratio becomes 5:9. Present age of A is?

A. 114 years

B. 49 years

C. 57 years

D. 62 years

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Correct Answer: Option C

Explanation:
Let ages 3k and 6k. Then (3k + 11)/(6k + 11) = 5/9. Solving gives k ≈ 19, age of A = 3*19 = 57.

This question belongs to: Maths Ratio and Proportion

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