Refrigerator COP = Q₂/W. If Q₂=300J, W=100J, COP is:

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COP = desired output/work input = 300/100 = 3. Typical COP > 1 for refrigerators. Memory aid: 'COP = cooling effect per work; higher = more efficient'. Thermodynamics calculation frequently tested in competitive exams.

Refrigerator COP = Q₂/W. If Q₂=300J, W=100J, COP is: MCQ with Answer and Explanation

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