Refrigerator COP = Q₂/W. If Q₂=300J, W=100J, COP is: MCQ with Answer and Explanation

Refrigerator COP = Q₂/W. If Q₂=300J, W=100J, COP is:
A. 200
B. 400
C. 0.33
D. 3
Answer: Option D
Solution (By JKSSB Mock Tests)
COP = desired output/work input = 300/100 = 3. Typical COP > 1 for refrigerators. Memory aid: 'COP = cooling effect per work; higher = more efficient'. Thermodynamics calculation frequently tested in competitive exams.

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