Student A gets 20% marks and fails by 30 marks. Student B gets 32% marks and gets 42 marks more than passing. Find the total marks. MCQ with Answer and Explanation

Student A gets 20% marks and fails by 30 marks. Student B gets 32% marks and gets 42 marks more than passing. Find the total marks.
A. 600
B. 500
C. 800
D. 700
Answer: Option A
Solution (By JKSSB Mock Tests)
Difference in percentage = 32% - 20% = 12%. Difference in marks = 42 + 30 = 72. 12% of Total = 72. Total = 600.

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Practice More Percentage Questions

Question #1
If the price of wheat increases by 30%, by how much percent must consumption be reduced to keep expenditure constant?
A. 25%
B. 23.08%
C. 20%
D. 22.5%

Correct Answer: Option B


Explanation:
Reduction % = (30/130)×100 ≈ 23.08%.

This question belongs to: Maths Percentage
Question #2
A number divided by 5, quotient increased by 20% then decreased by 20% gives 480. Number:
A. 2200
B. 2500
C. 2400
D. 2000

Correct Answer: Option B


Explanation:
(N/5)×1.2×0.8=480 → (N/5)×0.96=480 → N/5=500 → N=2500.

This question belongs to: Maths Percentage
Question #3
A trader bought articles for Rs. 1200. Ten were damaged, rest sold at Rs. 2 more than CP each, total profit Rs. 60. Number of articles:
A. 110
B. 100
C. 90
D. 80

Correct Answer: Option B


Explanation:
Let n articles, CP each = 1200/n. Sold (n-10) at (1200/n + 2). Total SP = (n-10)(1200/n +2) = 1260. Solving gives n=100.

This question belongs to: Maths Percentage