Temperature where Fahrenheit reading is double Celsius reading: MCQ with Answer and Explanation

Temperature where Fahrenheit reading is double Celsius reading:
A. 160°C
B. 80°C
C. 320°C
D. 40°C
Answer: Option A
Solution (By JKSSB Mock Tests)
F = (9/5)C + 32. Given F = 2C: 2C = 1.8C + 32 ⇒ 0.2C = 32 ⇒ C = 160°. Verify: F = 2×160 = 320°; formula: (9/5)×160+32 = 288+32 = 320°. Memory aid: Solve linear equation for temperature conversion problems. Algebraic manipulation of scale relations frequently tested in competitive exams.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1
A stone is thrown vertically upward with velocity 49 m/s. The time after which it returns to thrower is (g=9.8)
A. 15 s
B. 2.5 s
C. 10 s
D. 5 s

Correct Answer: Option C


Explanation:
Time of flight T = 2u/g = 2×49/9.8 = 98/9.8 = 10 s. Up and down symmetric. Max height = u²/(2g) = 122.5 m.

This question belongs to: Science Physics
Question #2
At what depth below the surface of the Earth does the acceleration due to gravity become zero?
A. It never becomes zero
B. At a depth equal to half the radius of the Earth
C. At a depth equal to one-fourth the radius of the Earth
D. At the center of the Earth

Correct Answer: Option D


Explanation:
The acceleration due to gravity at a depth 'd' is given by g' = g(1 - d/R), where R is the radius of the Earth. If we go to the center of the Earth, the depth 'd' becomes exactly equal to R. Substituting d = R into the formula gives g' = g(1 - R/R) = g(1 - 1) = 0. So, gravity is zero at the core.

This question belongs to: Science Physics
Question #3
If the distance between two charges is doubled, the electrostatic force between them will become:
A. One-fourth
B. Double
C. Four times
D. Half

Correct Answer: Option A


Explanation:
According to Coulomb's Law, the electrostatic force (F) between two point charges is inversely proportional to the square of the distance (r) between them (F ∝ 1/r²). If the distance is doubled (r becomes 2r), the new force F' ∝ 1/(2r)² = 1/4r². Thus, the force becomes one-fourth of its original value.

This question belongs to: Science Physics