The device used to convert DC to AC is MCQ with Answer and Explanation

The device used to convert DC to AC is
A. Generator
B. Inverter
C. Rectifier
D. Transformer
Answer: Option B
Solution (By JKSSB Mock Tests)
Inverter converts DC to AC. Rectifier AC to DC.

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Practice More Physics Questions

Question #1
A metal rod of length L at temperature T₀ is heated to temperature T. If α is the coefficient of linear expansion, the new length is:
A. Lα(T - T₀)
B. L(1 + αT)
C. L[1 + α(T - T₀)]
D. L(1 + αT₀)

Correct Answer: Option C


Explanation:
Linear expansion formula: ΔL = L₀αΔT, where ΔT = T - T₀. Thus new length L' = L₀ + ΔL = L₀[1 + α(T - T₀)]. Option A incorrectly uses absolute temperature T instead of temperature change. Option C gives only the change, not total length. Option D uses initial temperature incorrectly. Memory aid: 'Expansion depends on temperature change, not absolute value'. This standard formula application is common in thermal physics questions. Always identify initial length and temperature reference point to avoid sign errors.

This question belongs to: Science Physics
Question #2
A person cannot see objects clearly beyond 2 m. This defect of vision is:
A. Myopia
B. Presbyopia
C. Astigmatism
D. Hypermetropia

Correct Answer: Option A


Explanation:
Myopia (nearsightedness) is the inability to see distant objects clearly, with far point less than infinity. Here, far point is 2 m. Corrected using concave lens. Hypermetropia (farsightedness) affects near vision; presbyopia is age-related loss of accommodation; astigmatism involves uneven corneal curvature. Memory aid: 'Myopia = near-sighted; far point reduced'. This application question tests knowledge of vision defects and corrections, frequently appearing in competitive exams. Always link symptom (blurred distant vision) to defect (myopia) and correction (diverging lens).

This question belongs to: Science Physics
Question #3
A train 100 m long crosses a pole in 5 seconds. Its speed in km/h is
A. 36 km/h
B. 72 km/h
C. 50 km/h
D. 20 km/h

Correct Answer: Option B


Explanation:
Speed = distance/time = 100 m / 5 s = 20 m/s. Convert to km/h: multiply by 18/5 => 20 × 18/5 = 72 km/h. Pole is a point, so train's own length is the distance crossed. Speed in km/h = m/s × (18/5). 20 × 18/5 = 72.

This question belongs to: Science Physics