The difference between simple interest and compound interest on a certain sum of money for 3 years at 5% per annum is Rs. 61. Find the sum. MCQ with Answer and Explanation

The difference between simple interest and compound interest on a certain sum of money for 3 years at 5% per annum is Rs. 61. Find the sum.
A. Rs. 8000
B. Rs. 7500
C. Rs. 9000
D. Rs. 8500
Answer: Option A
Solution (By JKSSB Mock Tests)
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 61 = P * (5/100)^2 * (3 + 5/100) => 61 = P * (1/400) * (3.05) => P = (61 * 400) / 3.05 = 24400 / 3.05 = Rs. 8000.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Compound Interest Questions

Question #1
The difference between simple interest and compound interest on a certain sum of money for 3 years at 10% per annum is Rs. 217. Find the sum.
A. Rs. 8000
B. Rs. 7000
C. Rs. 6500
D. Rs. 7500

Correct Answer: Option B


Explanation:
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 217 = P * (10/100)^2 * (3 + 10/100) => 217 = P * (1/100) * (3.1) => 217 = P * 0.031 => P = 217 / 0.031 = Rs. 7000.

This question belongs to: Maths Compound Interest
Question #2
Find the compound interest on Rs. 40000 for 1 year at 12% per annum, compounded quarterly.
A. Rs. 5020.34
B. Rs. 5100.00
C. Rs. 5210.50
D. Rs. 4800.00

Correct Answer: Option A


Explanation:
Quarterly rate = 12 / 4 = 3%. Time = 4 quarters. Amount = 40000 * (1 + 3/100)^4 = 40000 * (1.03)^4 = 40000 * 1.12550881 = Rs. 45020.35. Compound Interest = 45020.35 - 40000 = Rs. 5020.35. Correct option matches B layout metrics.

This question belongs to: Maths Compound Interest
Question #3
A sum of money invested at compound interest doubles itself in 10 years. In how many years will it become 4 times of itself?
A. 30 years
B. 20 years
C. 15 years
D. 25 years

Correct Answer: Option B


Explanation:
The sum doubles (2^1) in 10 years. It will become 4 (2^2) times in 2 * 10 = 20 years.

This question belongs to: Maths Compound Interest