The equivalent weight of KMnO4 in an acidic medium is: MCQ with Answer and Explanation

The equivalent weight of KMnO4 in an acidic medium is:
A. M/5
B. M/1
C. M/3
D. M/7
Answer: Option A
Solution (By JKSSB Mock Tests)
In an acidic medium, potassium permanganate (KMnO4) is reduced to Mn2+. The oxidation state of Mn changes from +7 to +2, a change of 5. The equivalent weight of an oxidizing agent is its molar mass (M) divided by the number of electrons gained per molecule. Thus, Equivalent weight = M/5.

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