The force between two charges is 10 N in vacuum. If a dielectric of constant 5 is inserted, force becomes MCQ with Answer and Explanation

The force between two charges is 10 N in vacuum. If a dielectric of constant 5 is inserted, force becomes
A. 10 N
B. 50 N
C. 2 N
D. 0.5 N
Answer: Option C
Solution (By JKSSB Mock Tests)
F_medium = F_vacuum / K = 10/5 = 2 N.

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Practice More Physics Questions

Question #1
One micron is equal to
A. 10⁻³ m
B. 10⁻⁶ m
C. 10⁻¹⁰ m
D. 10⁻⁹ m

Correct Answer: Option B


Explanation:
Micron or micrometer = 10⁻⁶ m.

This question belongs to: Science Physics
Question #2
A person of mass 60 kg stands on a weighing scale in an elevator accelerating upward at 2 m/s² (g=10). The reading is
A. 60 kg
B. 48 kg
C. 72 kg
D. 120 kg

Correct Answer: Option C


Explanation:
Apparent weight = m(g+a) = 60×(10+2) = 720 N, which corresponds to 72 kg mass on scale (if scale calibrated in kg under g=10). Reading 72 kg. Downward acceleration would reduce.

This question belongs to: Science Physics
Question #3
The critical angle for light passing from glass (n=1.5) to air is approximately:
A. 60°
B. 30°
C. 42°
D. 90°

Correct Answer: Option C


Explanation:
Critical angle θ_c for total internal reflection: sinθ_c = n₂/n₁, where n₁ > n₂. Here n₁=1.5 (glass), n₂=1 (air), so sinθ_c = 1/1.5 = 2/3 ≈ 0.6667 ⇒ θ_c = sin⁻¹(0.6667) ≈ 41.8° ≈ 42°. Memory aid: 'sinθ_c = 1/n for glass to air'. This calculation tests understanding of total internal reflection conditions, crucial for optics in competitive exams. Always ensure light travels from denser to rarer medium for TIR to be possible; otherwise, no critical angle exists.

This question belongs to: Science Physics