The frequency of a seconds pendulum is MCQ with Answer and Explanation

Explanation:
p = m v = 5 × 2 = 10 kg m/s. Direction same as velocity. Momentum vector. Unit kg·m/s.

Explanation:
Using Newton's second law: F = ma. First find acceleration: a = (v - u)/t = (20 - 10)/2 = 5 m/s². Then F = 5 kg × 5 m/s² = 25 N. Alternatively, using impulse-momentum theorem: FΔt = mΔv ⇒ F×2 = 5×(20-10) ⇒ F = 50/2 = 25 N. Both approaches confirm. This problem integrates kinematics with dynamics. Exam tip: When time interval is given, impulse-momentum method is often faster. Such questions assess ability to select appropriate physics principles for problem-solving in time-constrained exams.

Explanation:
W = Fd cosθ, cos90° = 0, so work zero. e.g., coolie carrying load horizontally.