The gravitational force between two objects of masses 2 kg and 3 kg separated by 2 m (G = 6.67×10⁻¹¹) is MCQ with Answer and Explanation

The gravitational force between two objects of masses 2 kg and 3 kg separated by 2 m (G = 6.67×10⁻¹¹) is
A. 6.67×10⁻¹¹ N
B. 1.0005×10⁻¹⁰ N
C. 2×10⁻¹⁰ N
D. 1×10⁻¹⁰ N
Answer: Option B
Solution (By JKSSB Mock Tests)
F = G m1 m2 / r² = 6.67×10⁻¹¹ × 6 / 4 = 6.67×10⁻¹¹ × 1.5 = 1.0005×10⁻¹⁰ N.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1
If the kinetic energy of a body is increased by 300%, its momentum will increase by:
A. 300%
B. 150%
C. 100%
D. 200%

Correct Answer: Option C


Explanation:
The relationship between kinetic energy (K) and momentum (p) is K = p² / 2m. If K is increased by 300%, the new kinetic energy K' = K + 3K = 4K. Since p = √(2mK), the new momentum p' = √(2m × 4K) = 2√(2mK) = 2p. The momentum has doubled. Percentage increase = [(2p - p)/p] × 100 = 100%.

This question belongs to: Science Physics
Question #2
A car moving at constant velocity of 10 m/s has net force acting on it equal to
A. Frictional force
B. Zero
C. Weight of car
D. Force of engine

Correct Answer: Option B


Explanation:
Constant velocity implies zero acceleration, net force = 0 by Newton's first law. Engine force balances friction and air resistance. Net force zero, not necessarily zero forces.

This question belongs to: Science Physics
Question #3
Escape velocity from a planet of mass M and radius R is v. For another planet of mass 4M and radius 2R, escape velocity is
A. 2v
B. √2 v
C. v
D. v/√2

Correct Answer: Option B


Explanation:
v_esc ∝ √(M/R). New ∝ √(4M/2R) = √(2M/R) = √2 √(M/R) = √2 v.

This question belongs to: Science Physics