The instrument used to measure the wavelength of light is: MCQ with Answer and Explanation

The instrument used to measure the wavelength of light is:
A. Spectrometer
B. Microscope
C. Interferometer
D. Telescope
Answer: Option A
Solution (By JKSSB Mock Tests)
Spectrometer measures wavelengths of light using diffraction gratings or prisms to disperse light and angular measurements. Interferometer (D) can also measure wavelength but spectrometer is the standard instrument for spectral analysis. Microscope and telescope magnify images, not measure wavelength. Memory tip: 'Spectrometer = wavelength measurement via dispersion; used in spectroscopy'. This instrument-application question tests practical physics knowledge, frequently examined in competitive exams. Always associate instruments with their primary function; competitive exams often test context-specific uses.

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Practice More Physics Questions

Question #1
A geyser of 2 kW heats water. Time to raise temperature of 5 kg water from 30°C to 50°C (specific heat 4200 J/kg°C) is
A. 210 s
B. 840 s
C. 105 s
D. 420 s

Correct Answer: Option A


Explanation:
Heat required Q = m c ΔT = 5 × 4200 × 20 = 420,000 J. Power 2000 W, time t = Q/P = 420000/2000 = 210 s.

This question belongs to: Science Physics
Question #2
A car travels first half distance at 40 km/h and second half at 60 km/h. Average speed is
A. 45 km/h
B. 50 km/h
C. 48 km/h
D. 52 km/h

Correct Answer: Option C


Explanation:
Average speed = 2v₁v₂/(v₁+v₂) = 2×40×60/(40+60) = 4800/100 = 48 km/h. Not arithmetic mean (50). For equal distances, harmonic mean of speeds. If times equal, arithmetic mean applies.

This question belongs to: Science Physics
Question #3
Which particle has no charge?
A. Proton
B. Alpha particle
C. Electron
D. Neutron

Correct Answer: Option D


Explanation:
Neutron is neutral (charge 0). Proton +e, electron -e. Alpha particle +2e. Neutron mass slightly more than proton. Discovered by Chadwick.

This question belongs to: Science Physics