The main ore of aluminium is: MCQ with Answer and Explanation

The main ore of aluminium is:
A. Cinnabar
B. Galena
C. Haematite
D. Bauxite
Answer: Option D
Solution (By JKSSB Mock Tests)
Bauxite (Al₂O₃·2H₂O) is the principal ore of aluminium. Haematite is Fe₂O₃, galena is PbS, cinnabar is HgS. Bauxite is refined by Bayer's process to produce alumina, then electrolytically reduced (Hall-Héroult process).

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Practice More chemistry Questions

Question #1
When a solution turns red litmus blue, its pH is likely to be:
A. 10
B. 4
C. 7
D. 1

Correct Answer: Option A


Explanation:
Red litmus turning blue indicates that the solution is basic. Basic solutions have a pH greater than 7. Among the options, 10 is the only value greater than 7. pH 1 and 4 are acidic (turn blue litmus red), and 7 is neutral (no change in litmus color).

This question belongs to: Science chemistry
Question #2
Which of the following non-metals is lustrous?
A. Carbon
B. Iodine
C. Phosphorus
D. Sulphur

Correct Answer: Option B


Explanation:
Luster is a characteristic physical property of metals, but some non-metals also exhibit a shiny appearance. Iodine is a non-metal that forms dark purple, lustrous crystalline solids. Sulphur is dull yellow, phosphorus is white/red and waxy, and carbon (as graphite/coal) is generally dull.

This question belongs to: Science chemistry
Question #3
The rate of effusion of gas A is 4 times that of gas B. If molar mass of B is 64 g/mol, molar mass of A is:
A. 16 g/mol
B. 128 g/mol
C. 256 g/mol
D. 4 g/mol

Correct Answer: Option D


Explanation:
Graham's law: r_A / r_B = √(M_B / M_A). 4 = √(64 / M_A) → square both sides: 16 = 64 / M_A → M_A = 64/16 = 4 g/mol (Helium).

This question belongs to: Science chemistry