The maximum number of electrons that can be associated with the quantum numbers n=3, l=1, m=-1 is: MCQ with Answer and Explanation

The maximum number of electrons that can be associated with the quantum numbers n=3, l=1, m=-1 is:
A. 1
B. 2
C. 6
D. 10
Answer: Option B
Solution (By JKSSB Mock Tests)
The quantum numbers n=3 and l=1 specify the 3p subshell. The magnetic quantum number m=-1 specifies one particular 3p orbital within that subshell. According to Pauli's Exclusion Principle, a single orbital can accommodate a maximum of two electrons, which must have opposite spins (+1/2 and -1/2).

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Which of the following elements has the highest second ionization energy?
A. Magnesium
B. Silicon
C. Sodium
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Correct Answer: Option C


Explanation:
Sodium has the electronic configuration [Ne]3s1. After losing one electron to form Na+, it achieves a highly stable noble gas configuration ([Ne]). Removing a second electron from this stable core requires an exceptionally large amount of energy. Thus, sodium has the highest second ionization energy among these elements.

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Question #2
If half-life of an element is 2 days, after 6 days fraction left is:
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Correct Answer: Option B


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Correct Answer: Option C


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