The phenomenon of resonance in sound is used in: MCQ with Answer and Explanation

The phenomenon of resonance in sound is used in:
A. Neither
B. Tuning forks
C. Both (a) and (b)
D. Musical instruments
Answer: Option C
Solution (By JKSSB Mock Tests)
Resonance (amplification at natural frequency) is exploited in musical instruments (e.g., guitar body resonates with string frequencies) and tuning forks (designed to vibrate at precise frequency for calibration). Memory tip: 'Resonance applications: musical instruments (amplify sound), tuning forks (frequency standard), bridges (avoid resonance to prevent collapse)'. This application question tests wave phenomena uses, frequently appearing in competitive exams. Always link physical principles to practical applications; competitive exams emphasize real-world relevance of physics concepts, including both beneficial and hazardous aspects of resonance.

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Practice More Physics Questions

Question #1
The decimal equivalent of binary number 1101 is
A. 13
B. 9
C. 11
D. 15

Correct Answer: Option A


Explanation:
1×8 + 1×4 + 0×2 + 1×1 = 13.

This question belongs to: Science Physics
Question #2
If the length of a wire is stretched to double its original length while keeping its volume constant, its new resistance will be:
A. Twice the original
B. Unchanged
C. Half the original
D. Four times the original

Correct Answer: Option D


Explanation:
Resistance R = rhoL/A. If the wire is stretched so length becomes L' = 2L, the volume (V = AL) must remain constant. Therefore, the new area A' must be A/2 to maintain V. The new resistance R' = rho(2L)/(A/2) = 4 * (rhoL/A) = 4R. Stretching a wire to double its length increases its resistance strictly by a factor of 4. This is a classic trap question compared to merely 'changing the wire'.

This question belongs to: Science Physics
Question #3
Atmospheric pressure at sea level is 1.013×10⁵ Pa. Equivalent height of mercury column (density 13600 kg/m³, g=9.8) is
A. 7.6 m
B. 13.6 m
C. 0.76 cm
D. 0.76 m

Correct Answer: Option D


Explanation:
P = ρgh => h = P/(ρg) = 1.013×10⁵/(13600×9.8) ≈ 0.76 m = 76 cm.

This question belongs to: Science Physics