The population of a town increases by 8% annually. If its present population is 2,33,280, what was it 2 years ago? MCQ with Answer and Explanation

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The population of a town increases by 8% annually. If its present population is 2,33,280, what was it 2 years ago?

A. 2,00,000

B. 1,80,000

C. 2,10,000

D. 1,90,000

Answer: Option A

Solution (By JKSSB Mock Tests)

Pop 2 yrs ago = 233280 / (1.08)² = 233280 / 1.1664 = 200000.

This question belongs to: Maths Percentage

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Question #1

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A number is increased by 15% and then decreased by 15%. If the resulting number is 782, what was the original number?

A. 780

B. 820

C. 800

D. 750

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Correct Answer: Option C

Explanation:
1.15 × 0.85 = 0.9775. 0.9775x = 782 → x = 782/0.9775 = 800.

This question belongs to: Maths Percentage

Question #2

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A man's monthly salary is Rs. 20000. He spends 20% on rent and 30% of the remaining on food. How much does he save?

A. 14000

B. 10000

C. 12000

D. 11200

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Correct Answer: Option D

Explanation:
Remaining after rent = 80% of 20000 = 16000. Spent on food = 30% of 16000 = 4800. Savings = 16000 - 4800 = 11200.

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Question #3

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If 20% of a number is added to another number, the second number increases by 50%. What is the ratio of the first number to the second number?

A. 1:2

B. 2:1

C. 5:2

D. 2:5

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Correct Answer: Option C

Explanation:
Let first = x, second = y. 0.2x + y = 1.5y → 0.2x = 0.5y → x/y = 0.5/0.2 = 5/2. Ratio = 5:2.

This question belongs to: Maths Percentage

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