The potential at a point due to a point charge is 10 V at distance 2 m. Potential at 4 m is MCQ with Answer and Explanation

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The potential at a point due to a point charge is 10 V at distance 2 m. Potential at 4 m is

A. 2.5 V

B. 10 V

C. 20 V

D. 5 V

Answer: Option D

Solution (By JKSSB Mock Tests)

V ∝ 1/r. So if r doubled, V halved = 5 V.

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AC RMS value defined for equivalent:

A. Charge flow

B. Voltage

C. Heating effect

D. Magnetic field

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Correct Answer: Option C

Explanation:
I_rms defined so I_rms²R = average power, same heating as DC current. For sine wave: I_rms = I₀/√2. Memory tip: 'RMS: heating equivalence; use RMS for power calculations'. AC fundamentals frequently tested in competitive exams.

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Question #2

Two 60 W bulbs are connected in series across 220 V. Each bulb power becomes (approximately)

A. 120 W

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Correct Answer: Option D

Explanation:
Each bulb R = 220²/60 ≈ 807 Ω. Series total R=1614 Ω, current = 220/1614 ≈0.136 A. Power per bulb = I²R = (0.136)²×807 ≈ 15 W.

This question belongs to: Science Physics

Question #3

A solid sphere and a hollow sphere of same mass and radius are rolled down an incline. Which reaches bottom first?

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C. Depends on material

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Correct Answer: Option B

Explanation:
Solid sphere has smaller moment of inertia (2/5 MR²) than hollow (2/3 MR²). Less energy in rotation, more in translation, faster.

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