The power of a lens is measured in MCQ with Answer and Explanation

The power of a lens is measured in
A. Watt
B. Metre
C. Lux
D. Dioptre
Answer: Option D
Solution (By JKSSB Mock Tests)
Dioptre (D) = m⁻¹. Power = 1/f in metres. Convex positive, concave negative. Optometry uses dioptre.

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Practice More Physics Questions

Question #1
A body moves with uniform acceleration. The graph between velocity and time is:
A. Straight line with positive slope
B. Parabola
C. Hyperbola
D. Straight line parallel to time axis

Correct Answer: Option A


Explanation:
Uniform acceleration means constant rate of change of velocity: a = dv/dt = constant. Thus v = u + at, a linear equation in t. Graph is straight line with slope = acceleration. Parallel to time axis (A) implies zero acceleration (constant velocity). Parabola (C) is for position-time under constant acceleration. Memory tip: 'v-t graph slope = acceleration; area = displacement'. This graph interpretation question tests kinematics fundamentals, frequently examined in competitive exams. Always link graph features to physical quantities: slope, area, intercepts have specific meanings in motion graphs.

This question belongs to: Science Physics
Question #2
Which component in an electrical circuit is specifically designed to melt and break the circuit in the event of an overload?
A. Resistor
B. Capacitor
C. Switch
D. Fuse

Correct Answer: Option D


Explanation:
A fuse is an electrical safety device consisting of a wire made of an alloy with a low melting point. If the current exceeds a safe limit (due to a short circuit or overload), the Joules heating (I²Rt) causes the wire to melt instantly, breaking the circuit and preventing fire or damage to appliances.

This question belongs to: Science Physics
Question #3
If the distance between two charges is doubled, the electrostatic force between them will become:
A. Four times
B. One-fourth
C. Half
D. Double

Correct Answer: Option B


Explanation:
According to Coulomb's Law, the electrostatic force (F) between two point charges is inversely proportional to the square of the distance (r) between them (F ∝ 1/r²). If the distance is doubled (r becomes 2r), the new force F' ∝ 1/(2r)² = 1/4r². Thus, the force becomes one-fourth of its original value.

This question belongs to: Science Physics