The price of a rare artifact was increased by r%. Later, the new price was decreased by r%. If the final price of the artifact is Rs. 1, what was its original price in Rs.? MCQ with Answer and Explanation

The price of a rare artifact was increased by r%. Later, the new price was decreased by r%. If the final price of the artifact is Rs. 1, what was its original price in Rs.?
A. (10000 - r^2) / 10000
B. (1 - r^2/100)
C. (10000) / (10000 - r^2)
D. 1
Answer: Option C
Solution (By JKSSB Mock Tests)
Let original price be P. P * (1 + r/100) * (1 - r/100) = 1. P * (1 - r^2/10000) = 1. P * ((10000 - r^2) / 10000) = 1. P = 10000 / (10000 - r^2).

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Percentage Questions

Question #1
Price of a commodity falls by 20%. To keep expenditure constant, consumption must increase by:
A. 30%
B. 15%
C. 25%
D. 20%

Correct Answer: Option C


Explanation:
New price 0.8, consumption multiplier needed = 1/0.8 = 1.25, increase 25%.

This question belongs to: Maths Percentage
Question #2
A number is added to 30% of itself and the sum is 780. Find the number.
A. 600
B. 550
C. 500
D. 650

Correct Answer: Option A


Explanation:
x + 0.3x = 1.3x = 780 → x = 600.

This question belongs to: Maths Percentage
Question #3
A number decreased by 20% becomes 64. The number is:
A. 76
B. 72
C. 80
D. 84

Correct Answer: Option C


Explanation:
0.8x = 64 → x = 80.

This question belongs to: Maths Percentage