The speed of two luxury sedans are in the ratio 6 : 7. If car A takes 2.1 hours to cover a specific lap distance, find the time taken by car B. MCQ with Answer and Explanation
The speed of two luxury sedans are in the ratio 6 : 7. If car A takes 2.1 hours to cover a specific lap distance, find the time taken by car B.
A. 2.0 hours
B. 1.5 hours
C. 1.8 hours
D. 2.2 hours
Answer: Option C
Solution (By JKSSB Mock Tests)
Ratio of speeds A:B = 6:7, so ratio of times taken A:B = 7:6. Given 7 parts = 2.1 hours for car A => 1 part = 0.3 hours. Time taken by car B = 6 parts = 6 * 0.3 = 1.8 hours.
Explanation:
Distance for A to run = 500 - 140 = 360 meters. Ratio of speeds A:B = 3:4. Time taken by A to run 360m is proportional to 360 / 3 = 120 units. In the same time, B runs 4 * 120 = 480 meters. B needs 500m to win but only reaches 480m. Thus, A wins, and B is 500 - 480 = 20 meters behind. A wins by 20 meters.
Two stations A and B are 450 km apart. A train leaves station A at 4:00 PM at 60 km/h. Another train leaves station B at 5:00 PM at 70 km/h traveling towards A. At what time will they meet?
Explanation:
By 5:00 PM, the first train has traveled for 1 hour and covered 60 km. Distance left between them = 450 - 60 = 390 km. Relative speed = 60 + 70 = 130 km/h. Time to meet after 5:00 PM = 390 / 130 = 3 hours. Meeting time = 5:00 PM + 3 hours = 8:00 PM.
No comments yet. Be the first to start the discussion!