The speed of two luxury sedans are in the ratio 6 : 7. If car A takes 2.1 hours to cover a specific lap distance, find the time taken by car B. MCQ with Answer and Explanation
The speed of two luxury sedans are in the ratio 6 : 7. If car A takes 2.1 hours to cover a specific lap distance, find the time taken by car B.
A. 1.8 hours
B. 2.2 hours
C. 2.0 hours
D. 1.5 hours
Answer: Option A
Solution (By JKSSB Mock Tests)
Ratio of speeds A:B = 6:7, so ratio of times taken A:B = 7:6. Given 7 parts = 2.1 hours for car A => 1 part = 0.3 hours. Time taken by car B = 6 parts = 6 * 0.3 = 1.8 hours.
Explanation:
New speed = 4/5 of usual speed => New time = 5/4 of usual time. Difference = 1/4 of usual time = 15 minutes. Normal time = 15 * 4 = 60 minutes.
Explanation:
New speed = 5/6 of usual speed => New time = 6/5 of usual time. Difference = 1/5 of usual time = 15 minutes. Usual time = 15 * 5 = 75 minutes.
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