The work done by a centripetal force in half revolution is MCQ with Answer and Explanation

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The work done by a centripetal force in half revolution is

A. Zero

B. mv²

C. 2F r

D. πrF

Answer: Option A

Solution (By JKSSB Mock Tests)

Centripetal force always perpendicular to displacement, work zero.

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Question #1

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A hydraulic lift has area ratio of output to input piston 10:1. Force applied 50 N on input piston lifts weight of

A. 5000 N

B. 50 N

C. 500 N

D. 5 N

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Correct Answer: Option C

Explanation:
F1/A1 = F2/A2 => F2 = (A2/A1) F1 = 10×50 = 500 N.

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Question #2

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Myopia (nearsightedness) is corrected by using

A. Cylindrical lens

B. Concave lens

C. Convex lens

D. Bifocal lens

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Correct Answer: Option B

Explanation:
Myopic eye focuses image in front of retina. A diverging (concave) lens spreads light so image falls on retina. Hypermetropia (farsightedness) corrected by convex lens. Bifocals for presbyopia. Cylindrical for astigmatism.

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Question #3

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The pitch of a sound depends on its

A. Speed

B. Wavelength

C. Frequency

D. Amplitude

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Correct Answer: Option C

Explanation:
Pitch is subjective perception of frequency. Higher frequency higher pitch. Amplitude determines loudness. Speed and wavelength related by v = fλ, but pitch is frequency-based. Human ear 20 Hz-20 kHz.

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