Two numbers are in ratio 11:4. Their difference is 116. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 11:4. Their difference is 116. What is their sum?

A. 292

B. 695

C. 585

D. 621

Answer: Option C

Solution (By JKSSB Mock Tests)

Numbers 11k, 4k. Difference |11-4|k = 116 ⇒ k = 16. Sum = (11+4)k ≈ 585.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

If a:b = 6:7 and b:c = 7:4, then a:b:c = ?

A. 5:7:5

B. 6:7:4

C. 6:8:4

D. 12:14:8

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Correct Answer: Option B

Explanation:
Combine ratios: a:b = 6:7, b:c = 7:4 ⇒ a:b:c = 6:7:4.

This question belongs to: Maths Ratio and Proportion

Question #2

Ratio of present ages of A and B is 5:8. After 6 years, the ratio becomes 6:11. Present age of A is?

A. 80 years

B. 160 years

C. 85 years

D. 74 years

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Correct Answer: Option A

Explanation:
Let ages 5k and 8k. Then (5k + 6)/(8k + 6) = 6/11. Solving gives k ≈ 16, age of A = 5*16 = 80.

This question belongs to: Maths Ratio and Proportion

Question #3

Find the mean proportional between 23 and 54.

A. 35

B. 77

C. 38

D. 70

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Correct Answer: Option A

Explanation:
Mean proportional = √(23 × 54) = √(1242) = 35.

This question belongs to: Maths Ratio and Proportion

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