Two numbers are in ratio 12:7. Their difference is 51. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 12:7. Their difference is 51. What is their sum?

A. 596

B. 228

C. 504

D. 456

Answer: Option D

Solution (By JKSSB Mock Tests)

Numbers 12k, 7k. Difference |12-7|k = 51 ⇒ k = 10. Sum = (12+7)k ≈ 456.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

Two numbers are in the ratio 7:4 and their sum is 257. Find the numbers.

A. 143 and 110

B. 322 and 184

C. 176 and 65

D. 161 and 92

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Correct Answer: Option D

Explanation:
Numbers = 7k and 4k. 7k + 4k = 257 ⇒ k = 23. Thus, numbers are 161 and 92.

This question belongs to: Maths Ratio and Proportion

Question #2

Two numbers are in ratio 5:12. Their difference is 93. What is their sum?

A. 404

B. 127

C. 313

D. 255

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Correct Answer: Option D

Explanation:
Numbers 5k, 12k. Difference |5-12|k = 93 ⇒ k = 13. Sum = (5+12)k ≈ 255.

This question belongs to: Maths Ratio and Proportion

Question #3

Find the mean proportional between 7 and 28.

A. 17

B. 14

C. 35

D. 28

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Correct Answer: Option B

Explanation:
Mean proportional = √(7 × 28) = √(196) = 14.

This question belongs to: Maths Ratio and Proportion

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