Two numbers are in ratio 6:12. Their difference is 108. What is their sum? MCQ with Answer and Explanation

Question

Share Report Error

Two numbers are in ratio 6:12. Their difference is 108. What is their sum?

A. 447

B. 207

C. 414

D. 554

Answer: Option C

Solution (By JKSSB Mock Tests)

Numbers 6k, 12k. Difference |6-12|k = 108 ⇒ k = 18. Sum = (6+12)k ≈ 414.

This question belongs to: Maths Ratio and Proportion

Request complete Subject PDF

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Ratio and Proportion Questions

Question #1

Two numbers are in ratio 8:5. Their difference is 125. What is their sum?

A. 519

B. 201

C. 403

D. 445

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option C

Explanation:
Numbers 8k, 5k. Difference |8-5|k = 125 ⇒ k = 41. Sum = (8+5)k ≈ 403.

This question belongs to: Maths Ratio and Proportion

Question #2

Milk and water are in ratio 9:4 in a 416 L mixture. Quantity of milk?

A. 288 L

B. 313 L

C. 128 L

D. 576 L

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option A

Explanation:
Total parts = 13. Milk = [9 / (9+4)] × 416 = 288 L.

This question belongs to: Maths Ratio and Proportion

Question #3

If a:b = 8:6 and b:c = 6:12, then a:b:c = ?

A. 8:7:12

B. 8:6:12

C. 16:12:24

D. 7:6:13

View Answer & Solution Discuss

Get Complete Subject PDF for Maths

Correct Answer: Option B

Explanation:
Combine ratios: a:b = 8:6, b:c = 6:12 ⇒ a:b:c = 8:6:12.

This question belongs to: Maths Ratio and Proportion

Explore All Ratio and Proportion MCQs