Two numbers are in ratio 7:12. Their difference is 101. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 7:12. Their difference is 101. What is their sum?

A. 304

B. 334

C. 152

D. 423

Answer: Option A

Solution (By JKSSB Mock Tests)

Numbers 7k, 12k. Difference |7-12|k = 101 ⇒ k = 20. Sum = (7+12)k ≈ 304.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

Two numbers are in ratio 6:8. Their difference is 69. What is their sum?

A. 224

B. 283

C. 368

D. 112

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Correct Answer: Option A

Explanation:
Numbers 6k, 8k. Difference |6-8|k = 69 ⇒ k = 34. Sum = (6+8)k ≈ 224.

This question belongs to: Maths Ratio and Proportion

Question #2

Two numbers are in ratio 6:12. Their difference is 108. What is their sum?

A. 414

B. 207

C. 554

D. 447

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Correct Answer: Option A

Explanation:
Numbers 6k, 12k. Difference |6-12|k = 108 ⇒ k = 18. Sum = (6+12)k ≈ 414.

This question belongs to: Maths Ratio and Proportion

Question #3

Milk and water are in ratio 3:7 in a 391 L mixture. Quantity of milk?

A. 153 L

B. 234 L

C. 117 L

D. 274 L

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Correct Answer: Option C

Explanation:
Total parts = 10. Milk = [3 / (3+7)] × 391 = 117 L.

This question belongs to: Maths Ratio and Proportion

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