Two numbers are in ratio 7:12. Their difference is 101. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 7:12. Their difference is 101. What is their sum?
A. 423
B. 304
C. 152
D. 334
Answer: Option B
Solution (By JKSSB Mock Tests)
Numbers 7k, 12k. Difference |7-12|k = 101 ⇒ k = 20. Sum = (7+12)k ≈ 304.

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Practice More Ratio and Proportion Questions

Question #1
Two numbers are in ratio 9:11. Their difference is 102. What is their sum?
A. 422
B. 200
C. 400
D. 482

Correct Answer: Option C


Explanation:
Numbers 9k, 11k. Difference |9-11|k = 102 ⇒ k = 51. Sum = (9+11)k ≈ 400.

This question belongs to: Maths Ratio and Proportion
Question #2
If a:b = 5:5 and b:c = 5:9, then a:b:c = ?
A. 4:5:10
B. 5:5:9
C. 5:6:9
D. 10:10:18

Correct Answer: Option B


Explanation:
Combine ratios: a:b = 5:5, b:c = 5:9 ⇒ a:b:c = 5:5:9.

This question belongs to: Maths Ratio and Proportion
Question #3
Milk and water are in ratio 5:7 in a 476 L mixture. Quantity of milk?
A. 198 L
B. 230 L
C. 396 L
D. 278 L

Correct Answer: Option A


Explanation:
Total parts = 12. Milk = [5 / (5+7)] × 476 = 198 L.

This question belongs to: Maths Ratio and Proportion