Two numbers are in ratio 7:12. Their difference is 133. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 7:12. Their difference is 133. What is their sum?

A. 399

B. 199

C. 507

D. 434

Answer: Option A

Solution (By JKSSB Mock Tests)

Numbers 7k, 12k. Difference |7-12|k = 133 ⇒ k = 26. Sum = (7+12)k ≈ 399.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 3:4. After 4 years, the ratio becomes 5:6. Present age of A is?

A. 66 years

B. 71 years

C. 60 years

D. 132 years

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Correct Answer: Option A

Explanation:
Let ages 3k and 4k. Then (3k + 4)/(4k + 4) = 5/6. Solving gives k ≈ 22, age of A = 3*22 = 66.

This question belongs to: Maths Ratio and Proportion

Question #2

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Milk and water are in ratio 7:7 in a 233 L mixture. Quantity of milk?

A. 232 L

B. 117 L

C. 116 L

D. 138 L

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Correct Answer: Option C

Explanation:
Total parts = 14. Milk = [7 / (7+7)] × 233 = 116 L.

This question belongs to: Maths Ratio and Proportion

Question #3

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Ratio of present ages of A and B is 4:4. After 6 years, the ratio becomes 5:5. Present age of A is?

A. 89 years

B. 81 years

C. 168 years

D. 84 years

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Correct Answer: Option D

Explanation:
Let ages 4k and 4k. Then (4k + 6)/(4k + 6) = 5/5. Solving gives k ≈ 21, age of A = 4*21 = 84.

This question belongs to: Maths Ratio and Proportion

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