Two numbers are in ratio 7:12. Their difference is 57. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 7:12. Their difference is 57. What is their sum?

A. 266

B. 114

C. 228

D. 364

Answer: Option C

Solution (By JKSSB Mock Tests)

Numbers 7k, 12k. Difference |7-12|k = 57 ⇒ k = 11. Sum = (7+12)k ≈ 228.

This question belongs to: Maths Ratio and Proportion

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Question #1

Two numbers are in ratio 7:12. Their difference is 133. What is their sum?

A. 507

B. 399

C. 434

D. 199

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Correct Answer: Option B

Explanation:
Numbers 7k, 12k. Difference |7-12|k = 133 ⇒ k = 26. Sum = (7+12)k ≈ 399.

This question belongs to: Maths Ratio and Proportion

Question #2

If a:b = 7:5 and b:c = 5:9, then a:b:c = ?

A. 7:5:9

B. 6:5:10

C. 14:10:18

D. 7:6:9

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Correct Answer: Option A

Explanation:
Combine ratios: a:b = 7:5, b:c = 5:9 ⇒ a:b:c = 7:5:9.

This question belongs to: Maths Ratio and Proportion

Question #3

Ratio of present ages of A and B is 5:5. After 5 years, the ratio becomes 6:7. Present age of A is?

A. 45 years

B. 39 years

C. 50 years

D. 90 years

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Correct Answer: Option A

Explanation:
Let ages 5k and 5k. Then (5k + 5)/(5k + 5) = 6/7. Solving gives k ≈ 9, age of A = 5*9 = 45.

This question belongs to: Maths Ratio and Proportion

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