Two numbers are in ratio 8:11. Their difference is 86. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 8:11. Their difference is 86. What is their sum?

A. 344

B. 152

C. 304

D. 427

Answer: Option C

Solution (By JKSSB Mock Tests)

Numbers 8k, 11k. Difference |8-11|k = 86 ⇒ k = 28. Sum = (8+11)k ≈ 304.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 6:4. After 9 years, the ratio becomes 9:6. Present age of A is?

A. 83 years

B. 95 years

C. 180 years

D. 90 years

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Correct Answer: Option D

Explanation:
Let ages 6k and 4k. Then (6k + 9)/(4k + 9) = 9/6. Solving gives k ≈ 15, age of A = 6*15 = 90.

This question belongs to: Maths Ratio and Proportion

Question #2

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Two numbers are in ratio 6:4. Their difference is 103. What is their sum?

A. 617

B. 500

C. 558

D. 250

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Correct Answer: Option B

Explanation:
Numbers 6k, 4k. Difference |6-4|k = 103 ⇒ k = 51. Sum = (6+4)k ≈ 500.

This question belongs to: Maths Ratio and Proportion

Question #3

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Two numbers are in the ratio 11:15 and their sum is 450. Find the numbers.

A. 181 and 267

B. 374 and 510

C. 214 and 229

D. 187 and 255

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Correct Answer: Option D

Explanation:
Numbers = 11k and 15k. 11k + 15k = 450 ⇒ k = 17. Thus, numbers are 187 and 255.

This question belongs to: Maths Ratio and Proportion

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