Two numbers are in ratio 6:4. Their difference is 103. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 6:4. Their difference is 103. What is their sum?

A. 250

B. 558

C. 617

D. 500

Answer: Option D

Solution (By JKSSB Mock Tests)

Numbers 6k, 4k. Difference |6-4|k = 103 ⇒ k = 51. Sum = (6+4)k ≈ 500.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 7:8. After 10 years, the ratio becomes 9:10. Present age of A is?

A. 294 years

B. 147 years

C. 152 years

D. 143 years

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Correct Answer: Option B

Explanation:
Let ages 7k and 8k. Then (7k + 10)/(8k + 10) = 9/10. Solving gives k ≈ 21, age of A = 7*21 = 147.

This question belongs to: Maths Ratio and Proportion

Question #2

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Find the mean proportional between 19 and 14.

A. 16

B. 19

C. 32

D. 33

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Correct Answer: Option A

Explanation:
Mean proportional = √(19 × 14) = √(266) = 16.

This question belongs to: Maths Ratio and Proportion

Question #3

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Two numbers are in the ratio 13:11 and their sum is 287. Find the numbers.

A. 138 and 127

B. 158 and 106

C. 143 and 121

D. 286 and 242

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Correct Answer: Option C

Explanation:
Numbers = 13k and 11k. 13k + 11k = 287 ⇒ k = 11. Thus, numbers are 143 and 121.

This question belongs to: Maths Ratio and Proportion

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