Two numbers are in the ratio 11:13 and their sum is 148. Find the numbers. MCQ with Answer and Explanation

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Two numbers are in the ratio 11:13 and their sum is 148. Find the numbers.

A. 50 and 90

B. 66 and 78

C. 132 and 156

D. 96 and 67

Answer: Option B

Solution (By JKSSB Mock Tests)

Numbers = 11k and 13k. 11k + 13k = 148 ⇒ k = 6. Thus, numbers are 66 and 78.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 5:6. After 9 years, the ratio becomes 7:7. Present age of A is?

A. 200 years

B. 100 years

C. 105 years

D. 95 years

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Correct Answer: Option B

Explanation:
Let ages 5k and 6k. Then (5k + 9)/(6k + 9) = 7/7. Solving gives k ≈ 20, age of A = 5*20 = 100.

This question belongs to: Maths Ratio and Proportion

Question #2

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Two numbers are in ratio 7:5. Their difference is 102. What is their sum?

A. 546

B. 504

C. 647

D. 252

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Correct Answer: Option B

Explanation:
Numbers 7k, 5k. Difference |7-5|k = 102 ⇒ k = 51. Sum = (7+5)k ≈ 504.

This question belongs to: Maths Ratio and Proportion

Question #3

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If a:b = 4:6 and b:c = 6:10, then a:b:c = ?

A. 4:7:10

B. 4:6:10

C. 8:12:20

D. 3:6:11

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Correct Answer: Option B

Explanation:
Combine ratios: a:b = 4:6, b:c = 6:10 ⇒ a:b:c = 4:6:10.

This question belongs to: Maths Ratio and Proportion

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