Two numbers are in the ratio 12:10 and their sum is 753. Find the numbers. MCQ with Answer and Explanation

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Two numbers are in the ratio 12:10 and their sum is 753. Find the numbers.

A. 408 and 340

B. 816 and 680

C. 429 and 320

D. 396 and 345

Answer: Option A

Solution (By JKSSB Mock Tests)

Numbers = 12k and 10k. 12k + 10k = 753 ⇒ k = 34. Thus, numbers are 408 and 340.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

If a:b = 3:6 and b:c = 6:9, then a:b:c = ?

A. 3:6:9

B. 2:6:10

C. 6:12:18

D. 3:7:9

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Correct Answer: Option A

Explanation:
Combine ratios: a:b = 3:6, b:c = 6:9 ⇒ a:b:c = 3:6:9.

This question belongs to: Maths Ratio and Proportion

Question #2

Ratio of present ages of A and B is 7:8. After 12 years, the ratio becomes 8:9. Present age of A is?

A. 154 years

B. 70 years

C. 77 years

D. 82 years

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Correct Answer: Option C

Explanation:
Let ages 7k and 8k. Then (7k + 12)/(8k + 12) = 8/9. Solving gives k ≈ 11, age of A = 7*11 = 77.

This question belongs to: Maths Ratio and Proportion

Question #3

Two numbers are in ratio 8:12. Their difference is 61. What is their sum?

A. 357

B. 320

C. 160

D. 452

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Correct Answer: Option B

Explanation:
Numbers 8k, 12k. Difference |8-12|k = 61 ⇒ k = 15. Sum = (8+12)k ≈ 320.

This question belongs to: Maths Ratio and Proportion

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