Two numbers are in ratio 7:11. Their difference is 125. What is their sum? MCQ with Answer and Explanation

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Two numbers are in ratio 7:11. Their difference is 125. What is their sum?

A. 345

B. 389

C. 153

D. 306

Answer: Option D

Solution (By JKSSB Mock Tests)

Numbers 7k, 11k. Difference |7-11|k = 125 ⇒ k = 31. Sum = (7+11)k ≈ 306.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 4:8. After 10 years, the ratio becomes 5:9. Present age of A is?

A. 96 years

B. 101 years

C. 192 years

D. 93 years

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Correct Answer: Option A

Explanation:
Let ages 4k and 8k. Then (4k + 10)/(8k + 10) = 5/9. Solving gives k ≈ 24, age of A = 4*24 = 96.

This question belongs to: Maths Ratio and Proportion

Question #2

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Two numbers are in the ratio 7:8 and their sum is 572. Find the numbers.

A. 296 and 283

B. 532 and 608

C. 266 and 304

D. 246 and 324

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Correct Answer: Option C

Explanation:
Numbers = 7k and 8k. 7k + 8k = 572 ⇒ k = 38. Thus, numbers are 266 and 304.

This question belongs to: Maths Ratio and Proportion

Question #3

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If a:b = 3:6 and b:c = 6:4, then a:b:c = ?

A. 6:12:8

B. 3:7:4

C. 2:6:5

D. 3:6:4

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Correct Answer: Option D

Explanation:
Combine ratios: a:b = 3:6, b:c = 6:4 ⇒ a:b:c = 3:6:4.

This question belongs to: Maths Ratio and Proportion

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