Ratio of present ages of A and B is 4:8. After 10 years, the ratio becomes 5:9. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 4:8. After 10 years, the ratio becomes 5:9. Present age of A is?

A. 93 years

B. 96 years

C. 192 years

D. 101 years

Answer: Option B

Solution (By JKSSB Mock Tests)

Let ages 4k and 8k. Then (4k + 10)/(8k + 10) = 5/9. Solving gives k ≈ 24, age of A = 4*24 = 96.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Two numbers are in ratio 7:12. Their difference is 133. What is their sum?

A. 399

B. 199

C. 434

D. 507

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Correct Answer: Option A

Explanation:
Numbers 7k, 12k. Difference |7-12|k = 133 ⇒ k = 26. Sum = (7+12)k ≈ 399.

This question belongs to: Maths Ratio and Proportion

Question #2

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Ratio of present ages of A and B is 3:5. After 5 years, the ratio becomes 5:6. Present age of A is?

A. 42 years

B. 84 years

C. 36 years

D. 47 years

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Correct Answer: Option A

Explanation:
Let ages 3k and 5k. Then (3k + 5)/(5k + 5) = 5/6. Solving gives k ≈ 14, age of A = 3*14 = 42.

This question belongs to: Maths Ratio and Proportion

Question #3

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Two numbers are in the ratio 4:10 and their sum is 595. Find the numbers.

A. 158 and 436

B. 168 and 420

C. 336 and 840

D. 184 and 396

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Correct Answer: Option B

Explanation:
Numbers = 4k and 10k. 4k + 10k = 595 ⇒ k = 42. Thus, numbers are 168 and 420.

This question belongs to: Maths Ratio and Proportion

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