Ratio of present ages of A and B is 4:8. After 10 years, the ratio becomes 5:9. Present age of A is? MCQ with Answer and Explanation

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Ratio of present ages of A and B is 4:8. After 10 years, the ratio becomes 5:9. Present age of A is?

A. 101 years

B. 96 years

C. 192 years

D. 93 years

Answer: Option B

Solution (By JKSSB Mock Tests)

Let ages 4k and 8k. Then (4k + 10)/(8k + 10) = 5/9. Solving gives k ≈ 24, age of A = 4*24 = 96.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 4:8. After 8 years, the ratio becomes 6:10. Present age of A is?

A. 49 years

B. 44 years

C. 88 years

D. 37 years

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Correct Answer: Option B

Explanation:
Let ages 4k and 8k. Then (4k + 8)/(8k + 8) = 6/10. Solving gives k ≈ 11, age of A = 4*11 = 44.

This question belongs to: Maths Ratio and Proportion

Question #2

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If a:b = 2:8 and b:c = 8:12, then a:b:c = ?

A. 4:16:24

B. 2:8:12

C. 2:9:12

D. 1:8:13

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Correct Answer: Option B

Explanation:
Combine ratios: a:b = 2:8, b:c = 8:12 ⇒ a:b:c = 2:8:12.

This question belongs to: Maths Ratio and Proportion

Question #3

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Two numbers are in ratio 6:12. Their difference is 108. What is their sum?

A. 414

B. 447

C. 554

D. 207

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Correct Answer: Option A

Explanation:
Numbers 6k, 12k. Difference |6-12|k = 108 ⇒ k = 18. Sum = (6+12)k ≈ 414.

This question belongs to: Maths Ratio and Proportion

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