Two numbers are in the ratio 4:10 and their sum is 595. Find the numbers. MCQ with Answer and Explanation

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Two numbers are in the ratio 4:10 and their sum is 595. Find the numbers.

A. 184 and 396

B. 336 and 840

C. 158 and 436

D. 168 and 420

Answer: Option D

Solution (By JKSSB Mock Tests)

Numbers = 4k and 10k. 4k + 10k = 595 ⇒ k = 42. Thus, numbers are 168 and 420.

This question belongs to: Maths Ratio and Proportion

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Question #1

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Ratio of present ages of A and B is 7:5. After 10 years, the ratio becomes 8:8. Present age of A is?

A. 127 years

B. 138 years

C. 266 years

D. 133 years

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Correct Answer: Option D

Explanation:
Let ages 7k and 5k. Then (7k + 10)/(5k + 10) = 8/8. Solving gives k ≈ 19, age of A = 7*19 = 133.

This question belongs to: Maths Ratio and Proportion

Question #2

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Milk and water are in ratio 7:2 in a 488 L mixture. Quantity of milk?

A. 399 L

B. 109 L

C. 758 L

D. 379 L

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Correct Answer: Option D

Explanation:
Total parts = 9. Milk = [7 / (7+2)] × 488 = 379 L.

This question belongs to: Maths Ratio and Proportion

Question #3

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Ratio of present ages of A and B is 5:8. After 6 years, the ratio becomes 6:11. Present age of A is?

A. 74 years

B. 160 years

C. 80 years

D. 85 years

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Correct Answer: Option C

Explanation:
Let ages 5k and 8k. Then (5k + 6)/(8k + 6) = 6/11. Solving gives k ≈ 16, age of A = 5*16 = 80.

This question belongs to: Maths Ratio and Proportion

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