Two numbers are in the ratio 7:8 and their sum is 572. Find the numbers. MCQ with Answer and Explanation

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Two numbers are in the ratio 7:8 and their sum is 572. Find the numbers.

A. 266 and 304

B. 296 and 283

C. 246 and 324

D. 532 and 608

Answer: Option A

Solution (By JKSSB Mock Tests)

Numbers = 7k and 8k. 7k + 8k = 572 ⇒ k = 38. Thus, numbers are 266 and 304.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1

If a:b = 5:3 and b:c = 3:7, then a:b:c = ?

A. 4:3:8

B. 5:4:7

C. 5:3:7

D. 10:6:14

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Correct Answer: Option C

Explanation:
Combine ratios: a:b = 5:3, b:c = 3:7 ⇒ a:b:c = 5:3:7.

This question belongs to: Maths Ratio and Proportion

Question #2

Two numbers are in the ratio 7:4 and their sum is 257. Find the numbers.

A. 176 and 65

B. 161 and 92

C. 322 and 184

D. 143 and 110

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Correct Answer: Option B

Explanation:
Numbers = 7k and 4k. 7k + 4k = 257 ⇒ k = 23. Thus, numbers are 161 and 92.

This question belongs to: Maths Ratio and Proportion

Question #3

Ratio of present ages of A and B is 7:8. After 10 years, the ratio becomes 9:10. Present age of A is?

A. 294 years

B. 147 years

C. 143 years

D. 152 years

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Correct Answer: Option B

Explanation:
Let ages 7k and 8k. Then (7k + 10)/(8k + 10) = 9/10. Solving gives k ≈ 21, age of A = 7*21 = 147.

This question belongs to: Maths Ratio and Proportion

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