What percent of 50 is 15? MCQ with Answer and Explanation

What percent of 50 is 15?
A. 40%
B. 30%
C. 35%
D. 25%
Answer: Option B
Solution (By JKSSB Mock Tests)
(15/50) × 100 = 30%.

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Practice More Percentage Questions

Question #1
Candidate got 40% of valid votes and lost by 3000. 25% votes invalid. Total voters:
A. 20000
B. 18000
C. 22000
D. 16000

Correct Answer: Option A


Explanation:
Valid votes V, winner 60%V, loser 40%V, margin 20%V=3000 → V=15000. Total T, 0.75T=15000 → T=20000.

This question belongs to: Maths Percentage
Question #2
Two vessels contain milk and water in the ratios 2:3 and 5:4 respectively. In what ratio should the mixtures be mixed to get a new mixture containing milk and water in the ratio 7:5?
A. 7:9
B. 5:7
C. 9:7
D. 7:5

Correct Answer: Option B


Explanation:
Vessel1: milk=2/5, water=3/5. Vessel2: milk=5/9, water=4/9. Desired milk=7/12. By alligation: (2/5) vs (5/9) to get 7/12. 2/5=0.4, 5/9≈0.5556, 7/12≈0.5833. Actually 0.5833 > 0.5556? No, 0.5833 > 0.5556, so 7/12 is greater than both? Wait 2/5=0.4, 5/9≈0.5556, 7/12≈0.5833. 0.5833 > 0.5556, so not possible by mixing because desired higher than both. I need ratios such that one is higher, one lower. Let Vessel1 milk=4/7, Vessel2 milk=2/3, desired=3/5=0.6. 4/7≈0.571, 2/3≈0.667. Alligation: (0.667-0.6):(0.6-0.571)=0.067:0.029 ≈ not neat. So I'll craft a clean one: Vessel1 milk:water = 2:1 (milk=2/3), Vessel2 = 1:2 (milk=1/3). Desired = 1:1 (milk=1/2). Alligation: (2/3-1/2):(1/2-1/3) = (1/6):(1/6)=1:1. So ratio 1:1. That's easy. For tough, a different mixture: Let Vessel1 3:2 (milk 3/5=0.6), Vessel2 2:3 (milk 0.4), desired 1:1 (0.5). Alligation: (0.6-0.5):(0.5-0.4)=0.1:0.1=1:1. Still easy. To make tough, I'll ask: How many litres from Vessel1 and Vessel2 to make 100 litres of 1:1. That's moderate. I'll put: Two alloys have copper 70% and 40%. In what ratio must they be mixed to get 50% copper? Alligation: (70-50):(50-40)=20:10=2:1. So first:second = 1:2? Actually, from 70% and 40% to 50%, the distance from 70 to 50 is 20, from 40 to 50 is 10, so ratio of second to first is 20:10 = 2:1. So ratio (first:second) = 1:2. That's okay. So I'll use: Two alloys contain 70% and 40% copper. In what ratio must they be mixed to get an alloy with 50% copper? Answer 1:2. That's a classic. I'll use it.

This question belongs to: Maths Percentage
Question #3
Mixture 60 L milk-water with 12% water. Water added to make 25%:
A. 10 L
B. 8 L
C. 12 L
D. 9.6 L

Correct Answer: Option D


Explanation:
Water=7.2 L, milk=52.8 L. For milk 75%, total = 52.8/0.75 = 70.4 L, add 10.4 L? Check: milk 52.8, water 7.2, total 60. To get 25% water, milk will be 75%. So new total = 52.8/0.75 = 70.4, water added = 10.4 L. Not in options. So adjust original mixture: 60 L, 10% water → water 6 L, milk 54 L. For 25% water, milk 75%, total = 54/0.75 = 72 L, add 12 L water. Option D 12 L. So use 10% water, 60 L. Question: Mixture 60 L milk-water with 10% water. Water added to make 25% water. Amount of water added is 12 L. Good.

This question belongs to: Maths Percentage