Which of the following is the strongest oxidizing agent based on standard reduction potentials?
A. F2 (E° = +2.87 V)
B. Zn2+ (E° = -0.76 V)
C. Li+ (E° = -3.05 V)
D. Cu2+ (E° = +0.34 V)
Answer: Option A
Solution (By JKSSB Mock Tests)
The standard reduction potential (E°) indicates the tendency of a species to gain electrons. A higher positive E° value means a greater tendency to be reduced, making it a stronger oxidizing agent. Fluorine (F2) has the highest standard reduction potential (+2.87 V), making it the strongest oxidizing agent among the choices.
Explanation:
The modern periodic law states that the physical and chemical properties of elements are periodic functions of their atomic numbers. This was proposed by Henry Moseley, correcting Mendeleev's periodic table which was based on atomic mass. Atomic number determines the electronic configuration and thus chemical properties.
Explanation:
Eutrophication is the excessive richness of nutrients (mainly nitrates and phosphates from fertilizers and sewage) in a lake or other body of water. This causes a dense growth of plant life (algal blooms) and depletion of oxygen, killing aquatic animals and disrupting the ecosystem.
Explanation:
Brass: Cu + Zn. Bronze: Cu + Sn. Steel: Fe + C. Duralumin: Al + Cu + Mg + Mn. Brass is corrosion-resistant and used in plumbing, musical instruments. Zinc content varies (5-45%). Brass with higher zinc is stronger but less ductile. Some brasses contain small amounts of other elements.
No comments yet. Be the first to start the discussion!