Which of the following physical quantities has the same dimensional formula as that of pressure? MCQ with Answer and Explanation

Which of the following physical quantities has the same dimensional formula as that of pressure?
A. Momentum per unit area
B. Force per unit length
C. Power per unit volume
D. Energy per unit volume
Answer: Option D
Solution (By JKSSB Mock Tests)
Pressure has dimensions [ML⁻¹T⁻²]. Energy per unit volume: Energy is [ML²T⁻²], volume is [L³], so [ML²T⁻²]/[L³] = [ML⁻¹T⁻²], matching pressure. Force per unit length is [MLT⁻²]/[L] = [MT⁻²]. Momentum per unit area is [MLT⁻¹]/[L²] = [ML⁻¹T⁻¹]. Power per unit volume is [ML²T⁻³]/[L³] = [ML⁻¹T⁻³]. This dimensional equivalence explains why pressure appears in Bernoulli's equation alongside energy density. Memory aid: Pressure and energy density both represent stored energy per spatial dimension.

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Practice More Physics Questions

Question #1
The work done in moving a unit positive charge from one point to another against an electric field is known as:
A. Electric Field Intensity
B. Electric Flux
C. Capacitance
D. Potential Difference

Correct Answer: Option D


Explanation:
By definition, the electric potential difference between two points in an electric field is the amount of external work required to move a unit positive charge (1 Coulomb) slowly and without acceleration from one point to the other against the electrostatic force. The SI unit of potential difference is the Volt (Joules/Coulomb).

This question belongs to: Science Physics
Question #2
Refractive index n = c/v. For glass n=1.5, light speed is:
A. 2×10⁸ m/s
B. 4.5×10⁸ m/s
C. 1.5×10⁸ m/s
D. 3×10⁸ m/s

Correct Answer: Option A


Explanation:
v = c/n = 3×10⁸/1.5 = 2×10⁸ m/s. Direct refractive index formula application. Memory tip: 'Higher n ⇒ slower light; v = c/n'. Basic optics calculation frequently tested in competitive exams to verify formula recall and unit handling.

This question belongs to: Science Physics
Question #3
A car moving at 72 km/h is brought to rest in 10 seconds. The deceleration is
A. 2.5 m/s²
B. 7.2 m/s²
C. 2 m/s²
D. 20 m/s²

Correct Answer: Option C


Explanation:
72 km/h = 72 × (5/18) = 20 m/s. Initial velocity u = 20 m/s, final v = 0, t = 10 s. Using v = u + at => 0 = 20 + a×10 => a = -2 m/s², so deceleration magnitude is 2 m/s². Conversion factor 5/18 is essential: multiply km/h by 5/18 to get m/s.

This question belongs to: Science Physics