Which of the following physical quantities has the same dimensional formula as that of pressure?
A. Momentum per unit area
B. Force per unit length
C. Power per unit volume
D. Energy per unit volume
Answer: Option D
Solution (By JKSSB Mock Tests)
Pressure has dimensions [ML⁻¹T⁻²]. Energy per unit volume: Energy is [ML²T⁻²], volume is [L³], so [ML²T⁻²]/[L³] = [ML⁻¹T⁻²], matching pressure. Force per unit length is [MLT⁻²]/[L] = [MT⁻²]. Momentum per unit area is [MLT⁻¹]/[L²] = [ML⁻¹T⁻¹]. Power per unit volume is [ML²T⁻³]/[L³] = [ML⁻¹T⁻³]. This dimensional equivalence explains why pressure appears in Bernoulli's equation alongside energy density. Memory aid: Pressure and energy density both represent stored energy per spatial dimension.
Explanation:
By definition, the electric potential difference between two points in an electric field is the amount of external work required to move a unit positive charge (1 Coulomb) slowly and without acceleration from one point to the other against the electrostatic force. The SI unit of potential difference is the Volt (Joules/Coulomb).
Explanation:
v = c/n = 3×10⁸/1.5 = 2×10⁸ m/s. Direct refractive index formula application. Memory tip: 'Higher n ⇒ slower light; v = c/n'. Basic optics calculation frequently tested in competitive exams to verify formula recall and unit handling.
Explanation:
72 km/h = 72 × (5/18) = 20 m/s. Initial velocity u = 20 m/s, final v = 0, t = 10 s. Using v = u + at => 0 = 20 + a×10 => a = -2 m/s², so deceleration magnitude is 2 m/s². Conversion factor 5/18 is essential: multiply km/h by 5/18 to get m/s.
No comments yet. Be the first to start the discussion!