Which particle has no charge? MCQ with Answer and Explanation

Which particle has no charge?
A. Neutron
B. Alpha particle
C. Electron
D. Proton
Answer: Option A
Solution (By JKSSB Mock Tests)
Neutron is neutral (charge 0). Proton +e, electron -e. Alpha particle +2e. Neutron mass slightly more than proton. Discovered by Chadwick.

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Practice More Physics Questions

Question #1
Simple pendulum period T = 2π√(l/g). If length quadrupled, T becomes:
A. Double
B. Four times
C. Same
D. Half

Correct Answer: Option A


Explanation:
T ∝ √l. If l' = 4l, T' = √4 × T = 2T. Period doubles when length quadruples. Memory aid: 'Pendulum: T ∝ √l; 4× length ⇒ 2× period'. Proportional reasoning frequently tested in competitive oscillations sections.

This question belongs to: Science Physics
Question #2
The Chandrasekhar Limit is a fundamental concept in astrophysics that determines the ultimate fate of a star. It is specifically defined as the maximum mass of a:
A. Red Giant
B. Black Hole
C. Neutron Star
D. White Dwarf

Correct Answer: Option D


Explanation:
Subrahmanyan Chandrasekhar calculated that a White Dwarf star cannot support itself against gravitational collapse if its mass exceeds approximately 1.44 times the mass of our Sun. This is the Chandrasekhar limit. Stars above this mass limit will eventually collapse further into a dense neutron star or a black hole.

This question belongs to: Science Physics
Question #3
If three resistors of 2 Ω, 3 Ω, and 6 Ω are connected in parallel, the equivalent resistance of the combination is:
A. 11 Ω
B. 1 Ω
C. 0.5 Ω
D. 2 Ω

Correct Answer: Option B


Explanation:
For resistors in parallel, the reciprocal of the equivalent resistance (1/Rp) is the sum of the reciprocals of individual resistances. 1/Rp = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6. Finding a common denominator (6): 1/Rp = 3/6 + 2/6 + 1/6 = 6/6 = 1. Therefore, Rp = 1 Ω.

This question belongs to: Science Physics