A 10 μF capacitor is charged to 100 V. Energy stored is MCQ with Answer and Explanation

A 10 μF capacitor is charged to 100 V. Energy stored is
A. 5 J
B. 0.05 J
C. 0.5 J
D. 50 J
Answer: Option B
Solution (By JKSSB Mock Tests)
E = ½CV² = ½ × 10×10⁻⁶ × 10000 = 0.05 J.

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Practice More Physics Questions

Question #1
A body moves along a straight line with v = 2t + 3. Acceleration after 2 s is
A. 3 m/s²
B. 7 m/s²
C. 2 m/s²
D. 5 m/s²

Correct Answer: Option C


Explanation:
a = dv/dt = 2, constant.

This question belongs to: Science Physics
Question #2
If the length of a simple pendulum is quadrupled (increased by a factor of 4), what happens to its time period?
A. It is halved.
B. It remains unchanged.
C. It doubles.
D. It quadruples.

Correct Answer: Option C


Explanation:
The time period of a simple pendulum is given by T = 2π√(L/g), where L is the length of the string and g is acceleration due to gravity. The time period is directly proportional to the square root of the length (T ∝ √L). If L becomes 4L, the new time period T' = √4 = 2 times the original. It doubles.

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Question #3
A wire of resistance 5 Ω is bent into a circle. The effective resistance between ends of a diameter is
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B. 2.5 Ω
C. 1.25 Ω
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Correct Answer: Option C


Explanation:
Circle total resistance 5 Ω. Across diameter, two halves in parallel, each half 2.5 Ω. Parallel: R = (2.5×2.5)/(2.5+2.5) = 6.25/5 = 1.25 Ω. Equal parallel resistors gives half of each.

This question belongs to: Science Physics