If the length of a simple pendulum is quadrupled (increased by a factor of 4), what happens to its time period? MCQ with Answer and Explanation

If the length of a simple pendulum is quadrupled (increased by a factor of 4), what happens to its time period?
A. It doubles.
B. It remains unchanged.
C. It is halved.
D. It quadruples.
Answer: Option A
Solution (By JKSSB Mock Tests)
The time period of a simple pendulum is given by T = 2π√(L/g), where L is the length of the string and g is acceleration due to gravity. The time period is directly proportional to the square root of the length (T ∝ √L). If L becomes 4L, the new time period T' = √4 = 2 times the original. It doubles.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1
The number of significant figures in the measurement 0.0050200 m is:
A. 5
B. 8
C. 7
D. 3

Correct Answer: Option A


Explanation:
According to the rules of significant figures, leading zeros (0.00) are never significant as they only indicate the position of the decimal point. However, trailing zeros after a decimal point are always significant. Therefore, in 0.0050200, the significant digits are 5, 0, 2, 0, and 0, making a total of 5 significant figures.

This question belongs to: Science Physics
Question #2
A person with myopia uses spectacles of power -2 D. Far point without glasses is
A. Infinity
B. 50 cm
C. 2 m
D. 25 cm

Correct Answer: Option B


Explanation:
For myopia, corrective lens forms image of distant object at far point. 1/f = 1/(-far point) - 1/(-∞) => -2 = -1/F => F = 0.5 m = 50 cm.

This question belongs to: Science Physics
Question #3
The sky appears blue due to
A. Scattering
B. Total internal reflection
C. Dispersion
D. Refraction

Correct Answer: Option A


Explanation:
Rayleigh scattering by air molecules, shorter wavelengths (blue) scattered more.

This question belongs to: Science Physics