A 2 kg object is raised to a height of 5 m. The work done against gravity (g=10) is MCQ with Answer and Explanation

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A 2 kg object is raised to a height of 5 m. The work done against gravity (g=10) is

A. 10 J

B. 100 J

C. 0 J

D. 50 J

Answer: Option B

Solution (By JKSSB Mock Tests)

Work = mgh = 2 × 10 × 5 = 100 J. Force = mg = 20 N, distance 5 m, work = 20 × 5 = 100 J. This becomes potential energy stored.

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Question #1

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A machine gun fires 60 bullets per minute, each of mass 10 g with velocity 600 m/s. The power developed by the gun is:

A. 300 W

B. 1800 W

C. 18000 W

D. 3000 W

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Correct Answer: Option B

Explanation:
Power = work done per unit time = kinetic energy imparted per second. KE per bullet = ½mv² = ½×0.01×(600)² = 1800 J. Bullets per second = 60/60 = 1. Thus power = 1800 J/s = 1800 W. Note: Mass conversion: 10 g = 0.01 kg. This problem combines kinetic energy formula with power definition. Exam tip: Always convert to SI units first (grams to kg, minutes to seconds). Such numerical problems test multi-step calculation skills and unit conversion proficiency essential for competitive examinations.

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Question #2

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The prefix 'Peta' in the SI system represents which power of 10?

A. 10^9

B. 10^18

C. 10^12

D. 10^15

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Correct Answer: Option D

Explanation:
In the SI system of prefixes, 'Peta' stands for 10^15. Other common large prefixes include Kilo (10^3), Mega (10^6), Giga (10^9), Tera (10^12), and Exa (10^18). It's crucial to memorize both positive and negative powers (like nano, pico, femto) for competitive exams.

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