A wire of resistance 10 Ω is stretched to double its length. Its new resistance is MCQ with Answer and Explanation

A wire of resistance 10 Ω is stretched to double its length. Its new resistance is
A. 40 Ω
B. 20 Ω
C. 10 Ω
D. 5 Ω
Answer: Option A
Solution (By JKSSB Mock Tests)
Resistance R = ρL/A. Volume constant: A ∝ 1/L. Stretching length to 2L reduces area to A/2. New R' = ρ(2L)/(A/2) = 4ρL/A = 4R = 40 Ω. Resistance proportional to (length)² when volume constant.

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Correct Answer: Option C


Explanation:
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Question #2
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Correct Answer: Option C


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If an object is placed at the center of curvature of a concave mirror, the image formed is:
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Correct Answer: Option B


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