A man walks from his sector quarters to a focal workshop at 4 km/h and arrives 15 minutes late. If he scales his speed to 6 km/h, he arrives 5 minutes early. Find the distance.
Explanation:
Let total distance be 100 km. First segment = 30 km; Time = 30 / 15 = 2 hours. Second segment = 70 km; Time = 70 / 35 = 2 hours. Total distance = 100 km, Total time = 4 hours. Average speed = 100 / 4 = 25 km/h.
Explanation:
Since time is inversely proportional to speed when distance is constant, the ratio of time taken is the reciprocal of the speed ratio: 1/3 : 1/5 = 5 : 3.
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