A body covers 12 m in the 2nd second and 20 m in the 4th second of its motion. Assuming uniform acceleration, what is its initial velocity? MCQ with Answer and Explanation

Question

A body covers 12 m in the 2nd second and 20 m in the 4th second of its motion. Assuming uniform acceleration, what is its initial velocity?

A. 2 m/s

B. 6 m/s

C. 4 m/s

D. 8 m/s

Answer: Option B

Solution (By JKSSB Mock Tests)

The distance covered in the nth second is Sn = u + a/2 * (2n - 1). For n=2: 12 = u + a/2 * (3) => 2u + 3a = 24. For n=4: 20 = u + a/2 * (7) => 2u + 7a = 40. Subtracting equations: 4a = 16 => a = 4 m/s^2. Substitute 'a' back: 2u + 3(4) = 24 => 2u = 12 => u = 6 m/s.

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When a body is taken to a height equal to radius of Earth from surface, its weight becomes

A. Half

B. Double

C. One-fourth

D. Same

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Correct Answer: Option C

Explanation:
g' = g (R/(R+h))². If h=R, g' = g (R/2R)² = g/4. Weight = mg' = mg/4, one-fourth. Above surface, g decreases with square of distance from centre.

This question belongs to: Science Physics