A body of mass 2 kg is raised to height 10 m and dropped. Potential energy just before dropping is (g=10) MCQ with Answer and Explanation

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A body of mass 2 kg is raised to height 10 m and dropped. Potential energy just before dropping is (g=10)

A. 200 J

B. 20 J

C. 0 J

D. 100 J

Answer: Option A

Solution (By JKSSB Mock Tests)

PE = mgh = 2×10×10 = 200 J.

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An object weights 10 N in air, 8 N in water. The buoyant force is

A. 10 N

B. 18 N

C. 8 N

D. 2 N

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Correct Answer: Option D

Explanation:
Loss in weight = buoyant force = 10 - 8 = 2 N. Weight of displaced water = 2 N. Volume of object = mass of displaced water / density. Archimedes principle.

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Question #2

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A projectile is fired with velocity u at angle 45° with horizontal. Its time of flight is (g = 10 m/s²)

A. √2 u/10

B. √2 u/5

C. u/5

D. u/5√2

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Correct Answer: Option A

Explanation:
T = 2u sinθ/g = 2u sin45°/10 = 2u(1/√2)/10 = √2 u/10. SSC often tests projectile basics.

This question belongs to: Science Physics

Question #3

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The wave property that determines pitch is

A. Speed

B. Wavelength

C. Amplitude

D. Frequency

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Correct Answer: Option D

Explanation:
Pitch related to frequency.

This question belongs to: Science Physics

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