A body starts from rest and moves with uniform acceleration a. The ratio of distances covered in the 1st, 2nd, and 3rd seconds of motion is: MCQ with Answer and Explanation
A body starts from rest and moves with uniform acceleration a. The ratio of distances covered in the 1st, 2nd, and 3rd seconds of motion is:
A. 1:4:9
B. 1:3:5
C. 1:1:1
D. 1:2:3
Answer: Option B
Solution (By JKSSB Mock Tests)
Distance covered in nth second: sₙ = u + a(2n-1)/2. With u=0, sₙ ∝ (2n-1). For n=1: 2(1)-1=1; n=2: 3; n=3:5. Thus ratio 1:3:5. This result holds for any uniformly accelerated motion starting from rest. The distances covered in successive equal time intervals follow odd number ratio. Memory aid: This is a standard result derivable from s = ut + ½at² by calculating s at t=n and t=n-1. Frequently appears in competitive exams testing equation of motion applications.
Explanation:
Sir C. V. Raman discovered the Raman effect in 1928: inelastic scattering of photons by molecules, changing wavelength, providing information about molecular structure. He received the Nobel Prize in Physics in 1930. Photoelectric effect: Einstein; relativity: Einstein; electromagnetic induction: Faraday. Memory tip: 'Raman = scattering of light'. This scientist-discovery question tests knowledge of Indian contributions to physics, commonly featured in competitive exams. Always link Nobel laureates to their specific awarded work.
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