A car accelerates from rest at 4 m/s² for 5 s, then moves at constant velocity for 5 s. Total distance is MCQ with Answer and Explanation

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A car accelerates from rest at 4 m/s² for 5 s, then moves at constant velocity for 5 s. Total distance is

A. 200 m

B. 100 m

C. 150 m

D. 50 m

Answer: Option C

Solution (By JKSSB Mock Tests)

Phase 1: s1 = ½×4×25 = 50 m, v=20 m/s. Phase 2: s2 = 20×5 = 100 m. Total 150 m.

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Question #1

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A bullet of mass 20 g is fired with velocity 200 m/s. Its momentum is

A. 4 kg m/s

B. 4000 kg m/s

C. 40 kg m/s

D. 0.4 kg m/s

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Correct Answer: Option A

Explanation:
Mass m = 20 g = 0.02 kg. Momentum p = m v = 0.02 × 200 = 4 kg m/s. Always convert mass to kg. Momentum unit kg·m/s.

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Question #2

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The work done in moving a unit positive charge from one point to another against an electric field is known as:

A. Electric Field Intensity

B. Capacitance

C. Electric Flux

D. Potential Difference

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Correct Answer: Option D

Explanation:
By definition, the electric potential difference between two points in an electric field is the amount of external work required to move a unit positive charge (1 Coulomb) slowly and without acceleration from one point to the other against the electrostatic force. The SI unit of potential difference is the Volt (Joules/Coulomb).

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